Giải bài 6 trang 23 SGK Hóa học 12 nâng cao

(A):  \(CH_3CH=O+HCN \rightarrow CH_3-CH(CN)-OH\)

(B):  \(CH_3-CH(OH)-CN+H_2O+H_3O^+\xrightarrow{{{t}^{o}}} CH_3-CH(OH)-COOH+NH_4^+\)

(C):  \(nCH_2=CH-COOH\xrightarrow{{xt,p,{t}^{o}}} (-CH_2-CH(COOH)-)_n\)

(D):  \(CH_3COCH_3+HCN \rightarrow CH_3-(OH)C(CN)-CH_3\)

(E):  \(CH_3-(OH)C(CN)-CH_3+H_3O^++H_2O\xrightarrow{{{t}^{o}}} CH_3-(OH)C(COOH)-CH_3+NH_4^+\)

        \(CH_3-(OH)C(COOH)-CH_3\xrightarrow{{H_2SO_4,{t}^{o}}} CH_2=C(COOH)-CH_3\)

(F):  \(CH_2=C(COOH)-CH_3\xrightarrow{{xt,p,{t}^{o}}} (-CH_2-(COOH)C(CH_3)-)_n\)