Giải bài 2 trang 210 – Bài 43 - SGK môn Vật lý lớp 10 Nâng cao

\( \rho ={{10}^{3}}\text{ }\left( kg/{{m}^{3}} \right);\text{ }{{\rho }_{KK}}=1,21\text{ }\left( kg/{{m}^{3}} \right) \)

\( \left. \begin{align} & {{p}_{A}}={{p}_{B}}+\dfrac{1}{2}{{\rho }_{KK}}{{v}^{2}} \\ & {{p}_{A}}={{p}_{B}}+\rho gh \\ \end{align} \right\} \)

\( \begin{align} & \Rightarrow h=\dfrac{{{\rho }_{KK}}{{v}^{2}}}{2\rho g}=\dfrac{1,{{21.15}^{2}}}{{{2.10}^{3}}.9,8}\approx 0,014\text{ }\left( m \right) \\ & h=1,4\text{ }\left( cm \right) \\ \end{align} \)